Question

Two pans of a balance are 31.8 cm apart. The fulcrum of the balance has been shifted 1.06 cm away from the center by a dishonest shopkeeper. By what percentage is the true weight of the goods being marked up by the shopkeeper

Answer 1

Answer:

The percentage = (1.06/15.9) x 100℅

= 6.67℅

Step-by-step explanation:

For the two pan to be balanced in other to measure an object's accurate weight, the fulcrum must be exactly in the mid point of the distance/separation between the two pans.

In the case in this question, the dishonest shopkeeper has shifted the fulcrum by 1.06cm.

The pan separation is 31.8cm

The fulcrum position must be 31.8/2 = 15.9cm, for it to be balanced.

The percentage by which the true weight marked up by the shopkeeper is:

(1.06/True fulcrum position) x 100℅