The answer is
x + 2 / x + 3
But I don’t see that answer so what would it be
1 answer:
The Answer is : (x - 3)/(x + 2) not x+2/x+3 Thus A) is your Answer Simplify the following: ((x^2 + x - 6) (x^2 - 9))/((x^2 - 4) (x^2 + 6 x + 9)) The factors of -6 that sum to are 3 and -2. So, x^2 + x - 6 = (x + 3) (x - 2): ((x + 3) (x - 2) (x^2 - 9))/((x^2 - 4) (x^2 + 6 x + 9)) The factors of 9 that sum to 6 are 3 and 3. So, x^2 + 6 x + 9 = (x + 3) (x + 3): ((x + 3) (x - 2) (x^2 - 9))/((x + 3) (x + 3) (x^2 - 4)) (x + 3) (x + 3) = (x + 3)^2: ((x + 3) (x - 2) (x^2 - 9))/((x + 3)^2 (x^2 - 4)) x^2 - 4 = x^2 - 2^2: ((x + 3) (x - 2) (x^2 - 9))/((x^2 - 2^2) (x + 3)^2) Factor the difference of two squares. x^2 - 2^2 = (x - 2) (x + 2): ((x + 3) (x - 2) (x^2 - 9))/((x - 2) (x + 2) (x + 3)^2) x^2 - 9 = x^2 - 3^2: ((x + 3) (x - 2) (x^2 - 3^2))/((x - 2) (x + 2) (x + 3)^2) Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3): ((x - 3) (x + 3) (x + 3) (x - 2))/((x - 2) (x + 2) (x + 3)^2) ((x + 3) (x - 2) (x - 3) (x + 3))/((x - 2) (x + 2) (x + 3)^2) = (x - 2)/(x - 2)×((x + 3) (x - 3) (x + 3))/((x + 2) (x + 3)^2) = ((x + 3) (x - 3) (x + 3))/((x + 2) (x + 3)^2): ((x + 3) (x - 3) (x + 3))/((x + 2) (x + 3)^2) Combine powers. ((x + 3) (x - 3) (x + 3))/((x + 2) (x + 3)^2) = ((x + 3)^(1 + 1) (x - 3))/((x + 2) (x + 3)^2): ((x + 3)^(1 + 1) (x - 3))/((x + 3)^2 (x + 2)) 1 + 1 = 2: ((x + 3)^2 (x - 3))/((x + 2) (x + 3)^2) Cancel terms. ((x + 3)^2 (x - 3))/((x + 2) (x + 3)^2) = (x - 3)/(x + 2):Answer: (x - 3)/(x + 2)
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