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Alika [10]
3 years ago
7

2) Shawn's cat is currently stuck in a tree. Shawn has a ladder that is 15 feet long and he places the ladder 10 feet from the b

ase of the tree. At what angle of depression is Shawn's cat looking at him?

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Answer:

48.19°

Step-by-step explanation:

Check the attachment for the diagram.

The set up is a right angled triangle

Using the SOH, CAH, TOA trigonometry ratio to get the angle of depression theta.

The length of the ladder will be the hypotenuse of the triangle.

If he places the ladder 10 feet from the base of the tree, the adjacent of the triangle will be the base of the triangle.

Given Hypotenuse = 15feet

Adjacently = 10feet

According to CAH;

cos(theta) = Adjacent/Hypotenuse

cos(theta) = 10/15

cos(theta) = 2/3

theta = arccos(2/3)

theta = 48.19°

Shawn cat is looking at him at an angle of depression of 48.19°

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Answer:

Option C is the answer.

Step-by-step explanation:

To find the equation of the straight line equation i.e, we must be given with the two points \left (x_{1},y_{1} \right ) and \left (x_{2},y_{2}\right )

Since from the graph the two points closest to the line are\left ( 10,36 \right ) and \left ( 22,12 \right ).

Equation of line with two points closest to the line :

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on simplify we get,  m=-2.

Now, to find  the equation of the line:  y-y_{1}=m\cdot \left ( x-x_{1} \right )

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Adding both sides by 36, we get

y=-2x+20+36

y=-2x+56.

The equation for the linear  model in the scatter plot obtained by the two closest point \left ( 10,36 \right ) and \left ( 22,12 \right ) closest to the line is,

y=-2x+56










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