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Luba_88 [7]
3 years ago
15

If 5/6 gallons of paint covers 1/4 of the house, then how much paint is needed for the entire house?

Mathematics
1 answer:
tia_tia [17]3 years ago
6 0

Answer:

Step-by-step explanation:

1)  If \frac{5}{6} is needed to cover \frac{1}{4} than we need 3 more: \frac{5}{6}(3)=\frac{15}{6} =2\frac{3}{6} gallons2) But we still need to add the beginning [tex]\frac{5}{6}: 2\frac{3}{6}+\frac{5}{6}=2\frac{9}{6}=3\frac{3}6}=3.5

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Help me on this please
insens350 [35]

Answer:

A. x1/15

Step-by-step explanation:

6 0
3 years ago
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A 1970 comic book has appreciated 7% per year and originally sold for $0.35. What will the comic book be worth in 2017?
omeli [17]
You tell me if this makes sense to you.

It's 47 years from 1970 to 2017 so you would need to multiply 7% by the 47 years.

So: 0.07x47= 3.29 

Now you should add your new price to your original price: $3.29+$0.35= 3.64

So it should cost $3.64 now. Yes that does seem kind of low but that's how you do it.

I hope this helps :)
6 0
3 years ago
Help???????????,,,,,,,
Lemur [1.5K]

first convert the yards to feet....then add all of them together and subtract from 100

4 0
3 years ago
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Circle B has a center at point (0, 2) and a point W on the circle at (3, 3). Which equation represents a line that is tangent to
Solnce55 [7]

According to the given information, the equation represents a line that is tangent to the circle and goes through the point W is given by:

y = -x + 6.

<h3>What is the equation of the circle?</h3>

The equation of a circle of center (x_0,y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

In this problem, we have that the center is at point (0,2), hence:

x^2 + (y - 2)^2 = r^2

It goes through point (3,3), hence:

3^2 + (3 - 2)^2 = r^2

r^2 = 10

Hence, the equation is:

x^2 + (y - 2)^2 = 10

<h3>What is the equation of the tangent line at point W?</h3>

It is given by:

y - y(0) = \frac{dy}{dx}|_{W}(x - x(0))

Applying implicit differentiation, we have that:

2x + 2y\frac{dy}{dy} = 0

\frac{dy}{dx} = -\frac{x}{y}

Point W(3,3), hence:

(x_0, y_0) = (3,3)

\frac{dy}{dx} = -\frac{3}{3} = -1

Hence the equation is:

y - 3 = -(x - 3).

y = -x + 6.

More can be learned about the equation of a tangent line at brainly.com/question/8174665

5 0
2 years ago
Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 &lt; = x &lt; = 8. The length of the curve is . (Type an exact an
Mashutka [201]

Answer:

\sqrt\frac{387}{20}

Step-by-step explanation:

Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx

y=\dfrac{3}{5}x^{\frac{5}{3}}-  \dfrac{3}{4}x^{\frac{1}{3}}+6

\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}

1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})

=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}

For the Interval 1\leq x\leq 8

Length of the Curve =\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\

Using T1-Calculator

=\sqrt\frac{387}{20}

3 0
3 years ago
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