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Igoryamba
3 years ago
13

the number of patients treated at dr. whites dentist office each day for nine days is 4, 4, 5, 4, 4, 5, 5, 5, 4. find the mean,

median, mode, and range. round to the nearest 10 if necessary
Mathematics
1 answer:
GalinKa [24]3 years ago
3 0
Mean is 4.4 which is the average. median and mode is 4. Range is 1.
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Identify the figure that portrays the translation of the given preimage as indicated by the direction arrow.
ladessa [460]

The parallelogram will translate along the arrow and reach the head of the arrow.

The translation is a category of motion in which one body moves along towards a particular direction and reaches a particular point.

In translation, the rotational motion is not present. Also, the translational motion is a one-dimensional motion.

In the given figure, the parallelogram is present at the tail of the arrow.

The arrow depicts the direction of the translational motion.

So, the parallelogram will reach the end of the arrow as shown in the picture present in the attachment.

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2 years ago
Three teams, A, B and C, play in a competition.
VladimirAG [237]

Answer:

A = 24

B = 8

C = 6

Step-by-step explanation:

4:3 from B:C

8:6

8 games won by B and 6 games won by C.

3:1 from A:B

24:8

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8 0
3 years ago
A bag contains five white balls and five black balls. Your goal is to draw two black balls.
umka21 [38]

Answer:

a.) the probability that both the ball drawn are black  = \frac{10}{45} = \frac{2}{9}

b.) Sum of all the probabilities = \frac{\frac{2}{9} }{1 - \frac{2}{9} }  = \frac{\frac{2}{9} }{\frac{8}{9} }  = \frac{2}{8} =\frac{1}{4} = 0.25

Step-by-step explanation:

a) two balls are drawn at random .

   total number of balls   =  10

 number of black balls    =  5

  number of white balls    = 5.

   the number of ways two balls can be drawn = \binom{10}{2}  = \frac{10!}{2! 8!}  = \frac{10\times9}{2}  = 45

  the number of ways two black balls can be drawn = \binom{5}{2}  = \frac{5!}{2! 3!}  = \frac{5\times4}{2}  = 10

   the probability that both the ball drawn are black  = \frac{10}{45} = \frac{2}{9}

b) probability that First draw of two black balls = \frac{2}{9}

  probability that first draw is of two white balls is and second draw is of

  two black balls  = \frac{2}{9} \times\frac{2}{9}

  Probability that first two draws are of white balls and the third draw is of

  two black balls = \frac{2}{9} \times\frac{2}{9} \times\frac{2}{9}

  This is a geometric sequence and the final probability will be the sum of    

  all such probabilities, where we can take the the sequence to be an infinite series and the first term is \frac{2}{9} and the common ratio is \frac{2}{9}  which is less than 1.

  Sum of all the probabilities = \frac{\frac{2}{9} }{1 - \frac{2}{9} }  = \frac{\frac{2}{9} }{\frac{8}{9} }  = \frac{2}{8} =\frac{1}{4} = 0.25

3 0
3 years ago
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