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Lorico [155]
3 years ago
15

Jan's average score after fifteen tests was 82. Her average on the next five tests was 90. What was her average score for all tw

enty tests?
Mathematics
1 answer:
Leokris [45]3 years ago
4 0

Answer:

86

Step-by-step explanation:

82+90=172

172/2 (divided by two because thats how many numbers we added up to get 172)

172/2=86

86 is your answer

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A number increased by 7 is 2 less than twice the number
Vedmedyk [2.9K]

n + 7 = 2n - 2

Add 2 to both sides:

n + 9 = 2n

Isolate n:

n = 9

4 0
3 years ago
A cyclist travels 56 miles in 4 hours. What is the cyclist speed in feet per second
Step2247 [10]

Answer:

21.09 ft/s

Step-by-step explanation:

The first step is to create the ratio of speed/time.

\frac{56 miles}{4 hours}

Next we must simplify

\frac{14 miles}{1 hour}

Next we must convert 14 miles in to feet. There are 5280 feet in a mile.

14 * 5280ft = <u>75,920 feet</u>

Now for hours into seconds.

1 hour = 60 min, 60 min = 3600 seconds

Our new ratio is \frac{75920ft}{3600sec}

simplify.

75920ft / 3600sec = 21.09ft/s

3 0
3 years ago
25 (a square) - 4 (b square) + 28bc - 49 (c square)
LUCKY_DIMON [66]

Answer:

(5a - [2b - 7c]) and (5a + [2b + 7c])

Step-by-step explanation:

Factor 25a^2 - 4b^2 + 28bc - 49c^2.

Note that - 4b^2 + 28bc - 49c^2 involves the variables b and c, whereas 25a^2 has only one variable.  Thus, try to rewrite - 4b^2 + 28bc - 49c^2 as the square of a binomial:

- 4b^2 + 28bc - 49c^2 = -(4b^2 - 28bc + 49c^2), or

                                        -(2b - 7c)^2.

Thus, the original  25a^2 - 4b^2 + 28bc - 49c^2  looks like:

                               [5a]^2 - [2b - 7c]^2

Recall that a^2 - b^2 is a special product, the product of (a + b) and (a - b).  Applying this pattern to the problem at hand, we conclude:

Thus,   [5a]^2 - [2b - 7c]^2 has the factors (5a - [2b - 7c]) and (5a + [2b + 7c])

8 0
3 years ago
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Aleksandr-060686 [28]
By the number amount of the books like 1 biology and 2 mathematic book and 3 different novels or my grade
4 0
3 years ago
Any one that knows this please help thanks!
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8 0
3 years ago
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