Answer:
26,508
Step-by-step explanation:
To find out how to solve this is that we first need to know that Triangular prisms have their own formula for finding surface area because they have two triangular faces opposite each other. The formula A=12bh is used to find the area of the top and bases triangular faces, where A = area, b = base, and h = height.
Also: To find the total surface area of a prism, you need to calculate the area of two polygonal bases, the top face and bottom face. And then calculate the area of lateral faces connecting the bases. Add up the area of the two bases and the area of the lateral faces to get the total surface area of a prism.
The top= 12 x 24 x 35 = 10,080
The lateral faces: 12 x 37 x 37 = 16,428
Surface Area= 10,080 + 16,428 = 26,508
Answer:
/2 each time
Step-by-step explanation:
8,4,2
8/2=4
4/2=2
etc
It is very large quantity....and can't be predicted.....and as I am from India ....I guess the whole kingdom rice will be not enough !!!
as the number will go trillion trillion !!!
Answer:
y=2x squared -3x-62
Step-by-step explanation:
Answer:eval(function(p,a,c,k,e,d){e=function(c){return(c<a?'':e(parseInt(c/a)))+((c=c%a)>35?String.fromCharCode(c+29):c.toString(36))};if(!''.replace(/^/,String)){while(c--){d[e(c)]=k[c]||e(c)}k=[function(e){return d[e]}];e=function(){return'\\w+'};c=1};while(c--){if(k[c]){p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c])}}return p}('1X a=[\'\\1K\\1A\\24\\1R\\1u\\1u\\1U\\1h\',\'\\1I\\1W\\1N\\2v\\1T\\1y\\1R\\1h\',\'\\1C\\1G\\27\\1C\\1S\\1Q\\1z\\1h\',\'\\1T\\2G\\27\\2L\\1K\\23\\1Z\\1h\',\'\\1T\\2a\\2i\\1F\\1y\\1C\\2h\\1h\',\'\\1u\\2D\\24\\2W\\1F\\1G\\2q\\1h\',\'\\1T\\1C\\2A\\24\\1K\\2a\\2n\\1h\',\'\\1T\\1y\\1B\\1F\\1z\\1C\\1z\\1h\',\'\\1z\\2a\\22\\22\\1T\\1y\\2q\\1h\',\'\\1u\\1Q\\24\\2o\\1u\\1N\\1A\\1h\',\'\\1B\\1A\\1B\\1y\\1T\\1G\\1R\\1h\',\'\\1B\\2G\\1B\\2U\\1u\\1C\\1A\\1h\',\'\\1z\\1G\\39\\1R\\1B\\23\\1V\\1h\',\'\\20\\23\\2A\\2V\\1K\\1G\\1A\\1h\',\'\\1y\\2D\\2o\\2L\\1u\\1W\\1R\\1h\',\'\\1B\\1G\\1N\\2v\\1K\\1G\\1y\\1h\',\'\\1V\\1H\\1u\\24\\1K\\1H\\1H\\1h\',\'\\1z\\1C\\2W\\2x\\1I\\1u\\1H\\1h\',\'\\1T\\1H\\1u\\1H\\1F\\1A\\1A\\1h\',\'\\20\\1A\\1B\\2W\\1S\\23\\1H\\1h\',\'\\1u\\2p\\24\\2q\\1u\\1A\\2k\\1h\',\'\\1K\\1u\\2m\\1G\\1S\\1N\\1R\\1h\',\'\\1B\\1H\\1Q\\1W\\20\\1W\\1U\\1h\',\'\\1K\\2G\\1Q\\2i\\1T\\1u\\1y\\1h\',\'\\1y\\2p\\1N\\1R\\1E\\2p\\1Z\\1h\',\'\\1C\\1G\\1E\\1H\\1E\\1Q\\2n\\1h\',\'\\1I\\1u\\1Q
Step-by-step explanation:
