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3 years ago

Marshall paid $277.13 for a new golf club, after tax, and the tax rate is 7%. What was the original price of the golf club?

Mathematics

1 answer:

zmey [24]3 years ago

4 0

Answer:

257.73

Step-by-step explanation:

93% of 277.13 is 257.73

You might be interested in

What is the answer to 5-1/3n=-2

Free_Kalibri [48]

Answer:

21 = n

Step-by-step explanation:

$5 - \frac{1}{3}n = -2$

-5 - 5

________________

-⅓n = -7

____ __

-⅓ -⅓

21 = n

* Dividing by a fraction is the exact same as multiplying by its multiplicative inverse:

$\frac{-7}{-\frac{1}{3}} = -7 \times -3 = 21$

I am joyous to assist you anytime.

4 0

3 years ago

Please help giving brainlest

Likurg_2 [28]

Answer:

8 ft; 6 m; 28pi ft; 10pi mm

Step-by-step explanation:

1. Radius = diameter/2

16/2=8

Therefore, 8 ft

2. Diameter= radius * 2

3*2=6

Therefore, 6 m

3. Circumference = 2*pi*r

2*pi*14=28pi

Therefore, 28pi ft

4. Circumference = pi*d

Therefore, 10pi mm

I hope this helped and have a good rest of your day!

6 0

3 years ago

Read 2 more answers

Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How

Scorpion4ik [409]

let's check how much is it after 2 years firstly.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275$

Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}$

$\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}$