2sinxcosx+(3)^.5(cosx)=0
cosx(2sinx+(3^.5))=0
[email protected]/2, 3pi/2
sinx=-3^.5/2
sinx=pi/3,5pi/3
theta values=pi/3,pi/2,3pi/2,5pi/3
Answer:
(1,4)
Step-by-step explanation:
2x-3y=-10
y=4x
Since the y is already isolated, you can use substitution to find the answer to this equation. Simply replace any y values in the first equation with 4x:
2x-3(4x)=-10
2x-12x=-10
-10x=-10
x=1
y=4(1)=4
Hope this helps!
Answer:
graph the equation by transforming the "parent graph" accordingly. ... For example, for a positive number c , the graph of y=x2+c is same as graph y=x2 shifted c units up. Similarly, the graph y=ax2 stretches the graph vertically by a factor of a .
Step-by-step explanation:
AP and PB should add to AB
(2x-9)+(1.5x+6)=32
2x-9+1.5x+6=32
3.5x-3=32
3.5x=35
x=10
Plug this value of x in
1.5(10)+6
15+6
21
Final answer: 21
Answer:
if x is the number of years she is working that the equation would be: 24,500+x*((3/100)*24,500)
Step-by-step explanation:
For her 4th year x would be 4, so for the equation above x=4:
24500+4*((3/100)*24500)=27440