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3 years ago

Construct an equation that has n = 6 as its solution. Use n on both sides of the equation.

Mathematics

1 answer:

nevsk [136]3 years ago

4 0

Answer:

See Explanation

Step-by-step explanation:

Required

Determine any equation where n = 6

$n = 6$

Add n to both sides

$n + n = 6 + n$

$2n = 6 + n$ ----- This is 1 equation

$n = 6$

Multiply both sides by n

$n * n = 6 * n$

$n^2 = 6n$ ----- This is another

$n = 6$

Add 5n to both sides

$n + 5n = 6 + 5n$

$6n = 6 + 5n$ ---- This is another

Subtract 10 from both sides

$6n - 10 = 6 - 10 + 5n$

$6n - 10 = -4 + 5n$

$6n - 10 = 5n - 4$ --- This is another

You can have as many equations as possible

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University graduates have a mean job search time of 38.1 weeks, with a standard deviation of 10.1 weeks. The distribution of job

Lera25 [3.4K]

Answer:

7.1 weeks to 68.4 weeks

Step-by-step explanation:

Chebyshev's Theorem states that:

75% of the measures are within 2 standard deviations of the mean.

89% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 38.1

Standard deviation = 10.1

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Between 3 standard deviations of the mean.

So from 38.1 - 3*10.1 = 7.8 weeks to 38.1 + 3*10.1 = 68.4 weeks

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jeka57 [31]

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3 years ago

A sector with arc measure 72º has an

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$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's find the Radius ~

$\qquad \sf \dashrightarrow \: area = \frac{ \theta}{360} \times \pi {r}^{2}$

$\qquad \sf \dashrightarrow \: 80= \frac{ 72}{360} \times \pi {r}^{2}$

$\qquad \sf \dashrightarrow \: {r}^{2} = \frac{80 \times 360}{72 \times \pi}$

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$\qquad \sf \dashrightarrow \: {r}^{} = \sqrt\frac{400}{ \pi}$

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I hope you understood the whole procedure, let me know if you have doubts ~

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