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steposvetlana [31]
3 years ago
6

Can u prove 1=2????????

Mathematics
1 answer:
White raven [17]3 years ago
8 0

Answer:

YES

Step-by-step explanation:

1(6)-4 EQUALS 2


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Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
Can some one help me with this will give brainliest
a_sh-v [17]
The first one would be C and the 2nd is A. 
7 0
3 years ago
Assume that a sample is used to estimate a population proportion p. find the margin of error e that corresponds to the given sta
Leno4ka [110]

Let p be the proportion. Let c be the given confidence level , n be the sample size.

Given: p=0.3, n=1180, c=0.99

The formula to find the Margin of error is

ME = z _{\alpha/2}  \sqrt{\frac{p*(1-p)}{n}}

Where z (α/2) is critical value of z.

P(Z < z) = α/2

where α/2 = (1- 0.99) /2 = 0.005

P(Z < z) = 0.005

So in z score table look for probability exactly or close to 0.005 . There is no exact 0.005 probability value in z score table. However there two close values 0.0051 and 0.0049 . It means our required 0.005 value lies between these two probability values.

The z score corresponding to 0.0051 is -2.57 and 0.0049 is -2.58. So the required z score will be average of -2.57 and -2.58

(-2.57) + (-2.58) = -5.15

-5.15/2 = -2.575

For computing margin of error consider positive z score value which is 2.575

The margin of error will be

ME = z _{\alpha/2}  \sqrt{\frac{p*(1-p)}{n}}

= 2.575  \sqrt{\frac{0.30*(1-0.3)}{1180}}

= 2.575 * 0.0133

ME = 0.0342

The margin of error is 0.0342

7 0
3 years ago
Solve with explanation -4x+5&gt; - 5
Bezzdna [24]

Answer:

x < 2.5

Step-by-step explanation:

- 4x + 5 >  - 5 \\  - 4x >  - 5 - 5 \\  - 4x >  - 10 \\  \frac{ - 4x}{ - 4}  >  \frac{ - 10}{ - 4}  \\ x <  \frac{5}{2}  \\ x < 2.5

hope this helps

brainliest appreciated

good luck! have a nice day!

7 0
3 years ago
How do I do probability?
Katen [24]
Probability is the measurement of the likelihood of something happening

So, looking through the different questions, whether they have a graph or picture, you look at the numbers and divide by the total to determine the probablility.

Hope this helps
3 0
3 years ago
Read 2 more answers
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