5x3/8x3+11x2/12+2
15/24+22/24
15+22/24
37/24
1 13/24
If you want the regular fraction its 37/24, if you want the mixed fraction its 1 13/24
Answer:
![n = 5](https://tex.z-dn.net/?f=n%20%3D%205)
Step-by-step explanation:
Given
![2(n+1)! + 6n! = 3(n+1)!](https://tex.z-dn.net/?f=2%28n%2B1%29%21%20%2B%206n%21%20%3D%203%28n%2B1%29%21)
Required
Find n
Simplify (n + 1)!
![2(n+1)*n! + 6n! = 3(n+1)*n!](https://tex.z-dn.net/?f=2%28n%2B1%29%2An%21%20%2B%206n%21%20%3D%203%28n%2B1%29%2An%21)
Factorize
![n![2(n+1) + 6] = 3(n+1)*n!](https://tex.z-dn.net/?f=n%21%5B2%28n%2B1%29%20%2B%206%5D%20%3D%203%28n%2B1%29%2An%21)
Divide both sides by n!
![2(n+1) + 6 = 3(n+1)](https://tex.z-dn.net/?f=2%28n%2B1%29%20%2B%206%20%3D%203%28n%2B1%29)
Open brackets
![2n + 2 + 6 = 3n + 3](https://tex.z-dn.net/?f=2n%20%2B%202%20%2B%206%20%3D%203n%20%2B%203)
![2n + 8 = 3n + 3](https://tex.z-dn.net/?f=2n%20%2B%208%20%3D%203n%20%2B%203)
Collect like terms
![2n - 3n = 3 -8](https://tex.z-dn.net/?f=2n%20-%203n%20%3D%203%20-8)
![-n =-5](https://tex.z-dn.net/?f=-n%20%3D-5)
Multiply both sides by -1
![n = 5](https://tex.z-dn.net/?f=n%20%3D%205)
So first of all we can't start by changing them both into improper fractions
So it would be:
5/2 divided by 13/8
From there you would do 5/2 * 8/13 which could convert to
5/1 * 4/13 which would be 20/13
Answer:
35
Step-by-step explanation:
R × S = 15 could be 5 × 3 = 15, 3 × 5 = 15
15 × 1 = 15, 1 × 15 = 15
S ×T =3 From our previous step we can see that S could be 1 or 3 or 5 or 15.
Given that S×T =3, will make sense that S is 1 or 3
If S is 1 then T is 3 and if S is 3 then T is 1, so multiplied will give 3.
T×V=7 From previous step we see that T could be 1 or 3.
Since T×V = 7 it will make sense that T is 1, and therefore V is 7.
T ×V = 7, S ×T =3, R × S = 15, R × V = ??
1 × 7 = 7, S ×1 = 3, R × 3 = 15, 5 × 7 = ??
3 ×1 = 3, 5 × 3 = 15, 5 × 7 = 35