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koban [17]
3 years ago
10

21 POINTS FOR HELP!!!!!!! AND BRAINLIEST!!!!!

Mathematics
1 answer:
Alex Ar [27]3 years ago
6 0

Answer: 2cm

Step-by-step explanation:

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there are 20 children at a library 6 of the children have an average age of five years the remaining children have an average ag
Gelneren [198K]
20 total

6 have average of 5 years
6 x 5 = 30

20-6 = 14

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3 years ago
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In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.
Tema [17]

Answer:

Area  \approx 1149\ cm^2

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to \angle W)

Side u = 83 cm (It is the side opposite to \angle U)

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

A = \dfrac{1}{2}\times a\times b\times sinC

Where a and b are the two sides and

\angle C is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A  \approx 1149\ cm^2

So, the <em>area </em>of given triangle to the nearest square centimetre is:

Area  \approx 1149\ cm^2

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4 years ago
Solve for a a=.5×12ft (30ft+42ft)
Anastasy [175]
.5x12 (30+42)
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This is how you write 5.24 in expanded form 5+0.2+0.04
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