Answer:
5 units
Step-by-step explanation:
Let point O be the point of intersection of the kite diagonals.
|OF| = 2, |OH| = 5
|FH| = |OF| + |OH| = 2 + 5 = 7
FH and EG are the diagonals of the kite. Hence the area of thee kite is:
Area of kite EFGH = (FH * EG) / 2
Substituting:
35 = (7 * |EG|) / 2
|EG| * 7 = 70
|EG| = 10 units
The longer diagonal of a kite bisects the shorter one, therefore |GO| = |EO| = 10 / 2 = 5 units
x = |GO| = |EO| = 5 units
S = 2 * (pi) * r * h.....for r
divide both sides by 2 * pi * h
s / (2(pi)h = r
I’m ok lots of school work
Answer:
The answer is 4.802 × 10⁷
Step-by-step explanation:
48020000 = 4.802 × 10⁷
Thus, The answer is 4.802 × 10⁷
<u>-TheUnknownScientist</u>
Ans. 1 Angle E and angle F are corresponding angles.
Solution 2.
So,
angle E = angle F
=> x + 20 = 5x - 20
=> x + 20 + 20 = 5x
=> x + 40 = 5x
=> 40 = 5x - x
=> 40 = 4x
=> 40/4 = x
=> 10 = x
Solution 3.
E = x + 20
=> E = 10 + 20
=> E = 30
F = 5x - 20
=> F = 5(10) - 20
=> F = 50 - 20
=> F = 30
<em>Again</em><em> </em><em>justified</em><em> </em><em>that </em><em>they </em><em>are </em><em>equal</em><em> (</em><em> </em><em>besides</em><em> </em><em>answer </em><em>1</em><em>)</em><em>.</em>