Answer:

Step-by-step explanation:
Given

Required
Solve for C

Subtract 32 from both sides


Divide both sides by 1.8

Express the decimal as fraction


Simplify


Answer:
To find f-¹(x) of f(x) equate f(x) to y
That's
f(x) = y
So we have

Next interchange the variables that's x becomes y and y becomes x
That's

Next make y the subject
Cross multiply
We have
4y - 7 = 10x
Move -7 to the right side of the equation
4y = 10x + 7
Divide both sides by 4
We have the final answer as

So

Hope this helps you
Answer:
Triangles QUT and SVR are congruent because the defining two sides and an included angle of triangles QUT and SVR are equal
Step-by-step explanation:
Here we have QT = SR and
QV = SU
Therefore,
QT = √(UT² + QU²)........(1)
RS = √(VS² + RV²)..........(2)
Since QS = QU + SU = QV + VS ∴ QU = VS
Therefore, since SR = QT and QU = VS, then from (1) and (2), we have UT = RV
Hence since we know all sides of the triangles QUT and SVR are equal and we know that the angle in between two congruent sides of the the triangles QUT and SVR that is the angle in between sides QU and UT for triangle QUT and the angle in between the sides RV and VS in triangle SVR are both equal to 90°, therefore triangles QUT and SVR are congruent.
Answer:
5
Step-by-step explanation:
so 1/5 of 10 is 5 and 1/5 5 would be 1
area is LxW
so 5x1=5
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer