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2 years ago

Please answer this question

Mathematics

1 answer:

AleksandrR [38]2 years ago

6 0

250 miles because you pug the 5 in for g wich mack it 50×5=250

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Solve the equation for x, where x is a real number (5 points): -2x^2 + 5x - 10 = 3

KatRina [158]

Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                                      x = [ -b ± √(b^2 - 4ac) ] / (2a)
                                      x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
                                      x = [-5 ± √(25 - (104) ) ] / ( -4 )
                                      x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.

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3 years ago

Find the distance between the points (1,8) and (9, 2).

grin007 [14]

Answer:

$distance = \sqrt{(x_{1} -x_{2})^2+(y_{1} -y_{2})^2 }\\\\$

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3 years ago

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Nostrana [21]

Answer:

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2 years ago

For the set = {2,4,6}, determine n(A)

Katyanochek1 [597]

Answer:

n(A)= 10

Step-by-step explanation:

Hope it is ..mark me as brilliant

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2 years ago

Consider the function f ( x ) = 1 − 4 x 2 on the interval [ − 1 , 3 ] . Find the average or mean slope of the function on this i

Blababa [14]

Answer:

The average slope is 8.

Step-by-step explanation:

Let f be defined on the closed interval [a, b]. The average slope of f between a and b is the quotient

average slope = $\frac{f(b)-f(a)}{b-a}$

To find the average slope of the function $f(x)=1-4x^2$ on the interval [-1, 3] you have to evaluate your function in the interval and then divide by the interval.

So,

$f(-1)=1-4(-1)^2=-3\\\\f(3)=1-4(3)^2=-35$

The average slope is $\frac{f(3)-f(-1)}{3+1}= \frac{-3+35}{3+1}=\frac{32}{4}=8$

4 0

2 years ago