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Greeley [361]
3 years ago
7

Henry is making a corn grits recipe that calls for 1/4 cup of corn grits for every /12 cup of water. How much water will he need

if he uses 1/1/2 cups of corn grits?
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
4 0
Corn Grits : Water
1/4 : 1/2
1/4 x 4 : 1/2 x 4
1 : 2
3/2 : 2 x 3/2
1 1/2 : 3

So he will need 3 cup of water if he uses 1 1/2 cup of corns grits.
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0.73

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Which expression can be used to find the area of a circle with a diameter of 80 cm?
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3 years ago
What is -3/8 - (1/6)
Mrac [35]
Remove parentheses.

-3/8 -1/6

Find the Least Common Denominator (LCD) of 3/8, 1/6. In other words, find the Least Common Multiple (LCM) of 8,6.

LCD=24

Make the denominators the same as the LCD.

- 3x3/8x3 - 1x4/6x4

Simplify. Denominators are now the same

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7 0
3 years ago
Ben works at a mobile phone store, where he earns a flat $80 for each 8-hour shift. He also earns a commission of $20 for each p
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b

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he makes 80 dollars for a normal shift

20 dollars for every phone he sells 20m

and e is the total amount

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4 0
3 years ago
You are contacted by a phone-in technical support business that is interested in some information about the amount of time their
Gennadij [26K]

Answer:

The average hold time is 10.47 minutes.

Step-by-step explanation:

Let <em>X</em> = time the customers of a phone-in technical support business spend on hold.

The population mean of the random variable <em>X</em> is, <em>μ</em> = 11 minutes.

The population standard deviation of the random variable <em>X</em> is, <em>σ </em>= 1.16 minutes.

A random sample size, <em>n</em> = 62 callers are selected.

According to the Central limit theorem if large samples (<em>n</em> > 30) are selected from an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> then the sampling distribution of sample mean (\bar x) follows a Normal distribution.

The mean of the sampling distribution of sample mean is:

\mu_{\bar x}=\mu=11

The standard deviation of the sampling distribution of sample mean is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{1.16}{\sqrt{62}}=0.147

It is provided that P(\bar X>a)=0.79.

Compute the value of <em>a</em> as follows:

P(\bar X>a)=0.79\\P(Z>z)=0.79\\1-P(Z

The value of <em>z</em> for the above probability is, <em>z</em> = -0.806.

The value of <em>a</em> is:

z=\frac{a-\mu_{\bar x}}{\sigma_{\bar x}}\\-0.806=\frac{a-11}{0.147}\\a=11-(0.86\times 0.147)\\a=10.87

Thus, the average hold time is 10.47 minutes.

3 0
3 years ago
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