when it comes to a rational expression, we can get critical points from, zeroing the derivative "and" from zeroing the denominator alone, however the denominator provides critical valid points that are either "asymptotic" or "cuspics", namely that the function is not differentiable or not a "smooth line" at such spot.
if we get the critical points from the denominator on this one, we get x = ±1, both of which are cuspics. Check the picture below.
Answer:
The lines are perpendicular
Step-by-step explanation:
we know that
If two lines are parallel, then their slopes are the same
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)
Remember that
The formula to calculate the slope between two points is equal to
<em>Find the slope of the first line</em>
we have the points
(-3,-1) and (1,-9)
substitute in the formula
<em>Find the slope of the second line</em>
we have the points
(1,4) and (5,6)
substitute in the formula
Simplify
<em>Compare the slopes</em>
Find out the product
therefore
The lines are perpendicular