Answer:
A. 4,9 m/s2
B. 2,0 m/s2
C. 120 N
Explanation:
In the image, 1 is going to represent the monkey and 2 is going to be the package. Let a_mín be the minimum acceleration that the monkey should have in the upward direction, so the package is barely lifted. Apply Newton’s second law of motion:

If the package is barely lifted, that means that T=m_2*g; then:

Solving the equation for a_mín, we have:

Once the monkey stops its climb and holds onto the rope, we set the equation of Newton’s second law as it follows:
For the monkey: 
For the package: 
The acceleration a is the same for both monkey and package, but have opposite directions, this means that when the monkey accelerates upwards, the package does it downwards and vice versa. Therefore, the acceleration a on the equation for the package is negative; however, if we invert the signs on the sum of forces, it has the same effect. To be clearer:
For the package: 
We have two unknowns and two equations, so we can proceed. We can match both tensions and have:

Solving a, we have

We can then replace this value of a in one for the sums of force and find the tension T:

Answer:
0.017 m
Explanation:
Wavelength: This can be defined as the distance covered in one complete oscillation by a wave. The S.I unit of wave length is meter (m).
The expression for wave length is given as
v = λf ............................... Equation 1
Where v = speed of sound in air, λ = wave length of sound, f = frequency of sound.
make λ the subject of the equation,
λ = v/f ............................... Equation 2
Given: v = 340 m/s, f = 20000 Hz
Substitute into equation 2
λ = 340/20000
λ = 0.017 m.
Hence the wave length of sound in air = 0.017 m
Answer:
0.6A
Explanation:
Area of loop =200cm2 =200 x10 ∧-4m∧2 Change in Magnetic field (B)= 25mT -10mT =15mT time =5ms
From Faraday' s law of induction EMF(E)= change in magnetic field/time
E= 15mT/5ms
Note, that one weber per second is equivalent to one volt.
= 3V
from Ohm's law I =E/R
=3/5 =0.6A
Answer:
The efficiency of the engine is 40 %
Explanation:
Given;
input energy, = 2500 J
output energy, = 1000 J
The efficiency of the engine is given as;
Efficiency = output energy / input energy
Efficiency = 1000 / 2500
Efficiency = 0.4
Efficiency(%) = 0.4 x 100%
Efficiency = 40 %
Therefore, the efficiency of the engine is 40 %