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saveliy_v [14]
4 years ago
11

Help solving this math homework

Mathematics
1 answer:
Nostrana [21]4 years ago
5 0

8.

33 = 2y + 1 + y - 1

Add the 1 and -1

Add the y and 2y

33 = 3y

11 = y

9, AQ = 2y + 1

2(11) + 1

22 + 1

23

AQ = 23

10, QX = y - 1

QX = 11 - 1

10

QX = 10

11. 62 = 3x - 4 + 3x - 4

Add -4 and -4

Then add 3x + 3x

62 = 6x

Divide 62 by 6x

x = 11 2/3

AB = 3x - 4

3 (11 2/3) - 4

3 * 11 2/3 = 35

35 - 4 = 31

AB = 31

Both sides are equal, so BC also equals 31

12. 206 = 3x - 4  + 3x - 4

206 = 6x

x = 34 1/3

AB = 3x - 4

AB = 3(34 1/3) - 4

AB = 103

Because AB and BC are the same, BC also equals 103.

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Answer: There are 64 relations from A to B.

Step-by-step explanation:

Number of relation from set A to B = 2^{\text{ (Number of eklemnts in A x B)}}

=2^{\text{(Number of elements in set A  ) x (Number of elements in set B)}}

Since, A={Φ,{Φ},{Φ,{Φ}}} and B={1,2}

i.e. Number of elements in set A = 3

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So, Number of relation from set A to B = 2^{3\times 2}

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Hence, there are 64 relations from A to B.

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