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Answer:
Equation of other line passing through point (6 , - 11) and parallel to given line is y = - 23 x + 127 .
Step-by-step explanation:
Given as :
The equation of one line
y = - 23 x + 12
∵ The equation of line in slope-intercept form is
y = m x + c
where m is the slope of line and c is y-intercept
Now, Compare given line with standard line equation
So, The slope of given line = m = - 23
Now, Again
Other line is passing through point (6 , - 11) and is parallel to given line
so, both the lines are parallel
For parallel line condition , Slope of both lines are equal
Let The slope of other line = M
So, M = m = - 23
Now, Equation of other line passing through point (6 , - 11) and slope - 23 in slope-point form
y - = M × (x -
)
i.e y - ( - 11) = (- 23) × (x - 6)
Or, y + 11 = - 23 × x + 138
Or, y = - 23 x + 138- 11
i.e y = - 23 x + 127
So, The equation of other line y = - 23 x + 127
Hence, Equation of other line passing through point (6 , - 11) and parallel to given line is y = - 23 x + 127 . Answer
Answer:
Step-by-step explanation:
Let's factorize the 1st option :
⇒
⇒
⇒
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Finding the zeros :
⇒ Factors of numerator should be equated to 0
- x + 1 = 0 ⇒ x = -1
- x - 6 = 0 ⇒ x = 6
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Solution :