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Romashka [77]
3 years ago
6

On a particular day, the wind added 5 miles per hour to Jaime's rate when she was rowing with the wind and subtracted 5 miles pe

r hour from her rate on her return trip. Jaime found that in the same amount of time she could row 60 miles with the wind, she could go only 30 miles against the wind.What is her normal rowing speed with no wind?
Mathematics
1 answer:
AleksandrR [38]3 years ago
8 0
Jamie's normal rowing rate with no wind was 60 or 65 miles per hour

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10+3(2xz+3y)2xz what's the answer.
mamaluj [8]
10+3(2xz+3y)\cdot 2xz=10+(6xz+9y)\cdot 2xz=\\ \\=10+12x^2z^2+18xyz
3 0
3 years ago
Y= -3x+4 what is slope
Bas_tet [7]
Slope would be the -
6 0
2 years ago
Trevor is analyzing a circle, y2 + x2 = 49, and a linear function g(x). Will they intersect?
melomori [17]
We have a circumference that is given by the following equation:

x^{2}+y^{2}=49

We can write this equation in its standard form as follows:

 x^{2}+y^{2}=7^{2} \\ where \ the \ radius \ r=7

On the other hand, the linear function is given as the following table:

x \ \ \ \ \ \ \ \ g(x) \\ -1 \ \ -9.2 \\ 0 \ \ \ \ \ -9 \\ 1 \ \ \ \ \ -8.8

To check if the circle and the line intersects, let's substitute the equation of the line into the equation of the circle to see if there is a real solution, so:

x^{2}+(0.2x-9)^{2}=49 \\ \\ \therefore x^{2}+0.04x^{2}-3.6x+81=49 \\ \\ \therefore 1.04x^{2}-36x+32=0 \\ \\ Solving \ for \ x: \\ x_{1}=33.70 \\ x_{2}=0.91 \\ \\ Solving \ for \ y: \\ y_{1}=0.2(33.70)-9=-2.26 \\ y_{2}=0.2(0.91)-9=-8.18

 Finally the intersects are:

 P_{1}(33.70, -2.26) \ and \ P_{2}(0.91, -8.18)
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7 0
3 years ago
Read 2 more answers
Which graph is the solution to this system y-4x=-1y+x=4
natali 33 [55]

First, let's find the x and y intercepts

In the first equation

y - 4x = -1

Put x =0

y= - 1

(0, -1)

Put y=0 and the n solve for x

0 - 4x = -1

-4x = -1

x=0.25

(0.25 , 0)

The points for the first equation is (0, -1 ) and (0.25, 0)

Next is to find the intercts for the second equation

y + x = 4

put x=0

y = 4

(0, 4)

Put y =0

0 + x = 4

x = 4

( 4, 0)

The points for the second equation are;

(0, 4) and (4, 0)

Below is the graph

4 0
1 year ago
If a person flips a coin and then rolls a six dash sided die​, describe the sample space of possible outcomes using Upper H comm
xenn [34]

Answer:

Sample Space (S) = { (1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T) }  

Step-by-step explanation:

If a person flips a coin; the possible outcomes of flipping a coin are { Head (H), Tail (T) }

If a person rolls a six dash side die, the possible outcomes of rolling a dice are { 1, 2, 3, 4, 5, 6 }

Now, If a person flips a coin and then rolls a six dash side die;

The Sample Space (S) which is the set of all the possible outcomes of the activities carried out can be described as follows:

DIE                               COIN  →

↓                                      

                                        H                               T          

1                                      (1,H)                             (1,T)

2                                    (2,H)                             (2,T)

3                                    (3,H)                             (3,T)

4                                    (4,H)                             (4,T)

5                                    (5,H)                             (5,T)

6                                    (6,H)                             (6,T)

Sample Space (S) = { (1,H), (1,T), (2,H), (2,T), (3,H), (3,T), (4,H), (4,T), (5,H), (5,T), (6,H), (6,T) }  

3 0
3 years ago
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