A negatively charged object is placed within a positive electric field what happens to the object

2 answers:

8 0

The object becomes neutralized in charge. The positive charge in the field neutralizes the negative charge in the object.

Morgarella [4.7K]4 years ago

8 0

It will be pulled toward the source of the electric field.

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A helicopter travels west at 80 mph. It is moving above a car traveling on a highway at 80 mph. Given this information, you can

gavmur [86]

Answer:

d. at the same velocity

Explanation:

I will assume the car is also travelling westward because it was stated that the helicopter was moving above the car. In that case, it depends where the observer is. If the observer is in the car, the helicopter would look like it is standing still ( because both objects have the same velocity). If the observer is on the side of the road, both objects would be travelling at the same velocity. Also recall that, velocity is a vector quantity; it is direction-aware. Velocity is the rate at which the position changes but speed is the rate at which object covers distance and it is not direction wise. Hence velocity is the best option.

5 0

3 years ago

what is the average acceleration of a four wheeler that speeds up from 3 miles per hour to 15 miles per hour in 0.6 hours

den301095 [7]

A= change in velocity / change in time

$a = \frac{change \: in \: velocity}{change \: in \: time}$
$a = \frac{15 - 3}{0.6}$
$a = 20 \: \frac{m}{ {s}^{2} }$

6 0

4 years ago

What are the characteristics of S waves?

Reptile [31]

I think the answer is D

6 0

4 years ago

PLEASE HELP ME! THIS IS TIMED

vova2212 [387]

Vas happenin!!!

Hope your day is good

I would say observational tool

Hope this helps

*smiles*

6 0

3 years ago

Read 2 more answers

The human ear canal is about 2.9 cm long and can be regarded as a tube open at one end and closed at the eardrum. What is the fu

solniwko [45]

The frequency of the human ear canal is 2.92 kHz.

Explanation:

As the ear canal is like a tube with open at one end, the wavelength of sound passing through this tube will propagate 4 times its length of the tube. So wavelength of the sound wave will be equal to four times the length of the tube. Then the frequency can be easily determined by finding the ratio of velocity of sound to wavelength. As the velocity of sound is given as 339 m/s, then the wavelength of the sound wave propagating through the ear canal is

Wavelength=4*Length of the ear canal

As length of the ear canal is given as 2.9 cm, it should be converted into meter as follows:

$wavelength = 4*2.9*10^{-2} =0.116$

Then the frequency is determined as

f=c/λ=339/0.116=2922 Hz=2.92 kHz.

So, the frequency of the human ear canal is 2.92 kHz.

4 0

3 years ago