What is the restoring force of a spring stretched 0.35 meters with a spring contact of 55 newtons?
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Answer:
Explanation:
The period of the comet is the time it takes to do a complete orbit:
T=1951-(-563)=2514 years
writen in seconds:
Since the eccentricity is greater than 0 but lower than 1 you can know that the trajectory is an ellipse.
Therefore, if the mass of the sun is aprox. 1.99e30 kg, and you assume it to be much larger than the mass of the comet, you can use Kepler's law of periods to calculate the semimajor axis:
Then, using the law of orbits, you can calculate the greatest distance from the sun, which is called aphelion:
Okay here initially child walks on the outer edge of the disc and then started to move inside
So here as the child and Merry go round is an isolated system so there is no external Torque on this system from outside
As here we can see there is external force acting on this system by the hinge of the Merry go round as well as due to gravity so we can not use momentum conservation to solve such type of questions.
But as we can say that there is no external torque on this system about the hinge point so we will use conservation of angular momentum for this system
Here as we know that
where L = angular momentum
since here torque is ZERO
L = constant
so here we can write initial angular momentum of the system as
here we know that
= moment of inertia of merry go round
= moment of inertia of child
so here we can say
so here as the child moves from edge to inside the disc it moment of inertia will decrease because as we know that moment of inertia of child is given as
here m = mass of child
r = distance of child from center
Since child is moving inside so his distance from center is decreasing
so here moment of inertia of child is decreasing as he starts moving inside
so final angular speed of merry go round will increase as child go inside
so here as
final angular speed will be more than initial speed as child moves inside