Maybe you can split up the questions. I will try to answer your first question.
1. In an elastic collision, momentum is conserved. The momentum before the collision is equal to the momentum after the collision. This is a consequence of Newton's 3rd law. (Action = Reaction)
2. Momentum: p = m₁v₁ + m₂v₂
m₁ mass of ball A
v₁ velocity of ball A
m₂ mass of ball B
v₂ velocity of ball B
Momentum before the collision:
p = 2*9 + 3*(-6) = 18 - 18 = 0
Momentum after the collision:
p = 2*(-9) + 3*6 = -18 + 18 = 0
3: mv + m(-v) = m(-v) + m(v)
the velocities would reverse.
4.This question is not factual since the energy of an elastic collision must also be conserved. The final velocities should be: v₁ = -1 m/s and v₂ = 5 m/s. That said assuming the given velocities were correct:
before collision
p = 10*3 + 5*(-3) = 30 - 15 = 15
after collision:
p = 10*(-2) + 5 * v₂ = 15
v₂ = 7
5.You figure out.
Able to be hammered or pressed permanently out of shape without breaking or cracking.
Its simple, you have to plot in an example, but dont get confused with K, the answer its b
Answer:
No. of 100 W bulbs, n = 28,539 bulbs
Given:
Power of a single bulb = 100 W
Time period, T = 1 yr = 
= 31,536,000 s
mass of matter, m = 1 g = ![1\times 10^{-3}]](https://tex.z-dn.net/?f=1%5Ctimes%2010%5E%7B-3%7D%5D)
Solution:
According to Eintein's mass-energy equivalence:
E = 
E = 
E = 
Power of a single bulb, P = 
P = 
P = 28,53,881 W
No. of 100 W bulbs, n = 
n = 
n = 28,539
