Explanation:
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V = f(lambda)
5/1 = lambda
lambda = 5
C. <span>C. 5 m/s away from the waves</span>
<span>The magnitude of the rock is equal to g. After the rock is released, there are no more forces acting on it, yet gravity remains. The initial inputs, on a bridge, at an angle of 30 deg below horizontal do not matter after the release.</span>
<span>No, because the truck applies more pressure than the bridge can support.</span>
Answer:
Ts = 3.0×10¯² sec
Explanation:
From the question given:
Ts = 2π √(4.5×10¯² Kg / 2.0×10³ Kg/s²)
The above expression can be evaluated as follow:
Pi (π) = 3.14
Ts = 2π √(4.5×10¯² / 2.0×10³)
Ts = 2 × 3.14 √(4.5×10¯² / 2.0×10³)
Ts = 6.28 × √(2.25×10¯⁵)
Ts = 6.28 × 4.74×10¯³
Ts = 3.0×10¯² sec
