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2 years ago

The answer to 7/12 divided by 2

Mathematics

1 answer:

bija089 [108]2 years ago

3 0

Answer: 7/24

Step-by-step explanation: Think of the 2 as 2/1.

When dividing by a fraction, we can simply change, we can simply change the multiplication sig to division and take the reciprocal of the second fraction or flip the second fraction.

So our problem can be rewritten as $(\frac{7}{12})$ $x$ $(\frac{1}{2})$ .

Now multiplying across the top and bottom we get 7/24.

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Consider this cube with a volume of 64 cubic centimeters.

Eduardwww [97]

Answer:

This is a perfect cube.

The side length is 4.

Taking the cube root of the volume will determine the side length.

Step-by-step explanation:

We are told that:

A cube has volume 64 centimeters cubed.

The formula for the volume of a cube = s³

Where s = side length

Hence

64 cm³ = s³

We can find s by finding the cube root of both sides

Hence,

cube root(64) = cube root(s³)

s = 4 cm

Note that 64 is a perfect cube because 4 × 4 × 4 = 4³ = 64 cm³

Therefore, it can be concluded of the cube that:

This is a perfect cube.

The side length is 4.

Taking the cube root of the volume will determine the side length.

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2 years ago

A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 ft/s along

mina [271]

Answer:

The tip of the man shadow moves at the rate of $\frac{20}{3} ft.sec$

Step-by-step explanation:

Let's draw a figure that describes the given situation.

Let "x" be the distance between the man and the pole and "y" be distance between the pole and man's shadows tip point.

Here it forms two similar triangles.

Let's find the distance "y" using proportion.

From the figure, we can form a proportion.

$\frac{y - x}{y} = \frac{6}{15}$

Cross multiplying, we get

15(y -x) = 6y

15y - 15x = 6y

15y - 6y = 15x

9y = 15x

y = $\frac{15x}{9\\} y = \frac{5x}{3}$

We need to find rate of change of the shadow. So we need to differentiate y with respect to the time (t).

$\frac{dy}{t} = \frac{5}{3} \frac{dx}{dt}$ ----(1)

We are given $\frac{dx}{dt} = 4 ft/sec$ . Plug in the equation (1), we get

$\frac{dy}{dt} = \frac{5}{3} *4 ft/sect\\= \frac{20}{3} ft/sec$

Here the distance between the man and the pole 45 ft does not need because we asked to find the how fast the shadow of the man moves.

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Step-by-step explanation:

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