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Schach [20]
3 years ago
6

Help ASAP

Chemistry
1 answer:
tatuchka [14]3 years ago
6 0

The answer is; A

This process shown in the diagram is called phosphorylation. Phosphorylation is a significant biochemical process in the body since it is able to activate or deactivate molecules by influencing their chemical properties. An example of a significant phosphorylation process is that of the p53 tumor suppressor protein which is activated by the phosphorylation process.


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Correct me if I wrong but I think it's "c"
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HEL PHELP HE LP HELPPP ILL MARK U THE BRAINLIEST :)
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Answer:

C3H6

Explanation:

3 Carbon atoms

6 Hydrogen atoms

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Answer questions a-c about the Bronsted acid-base reaction below using the identifying letters A-D below each structure. The pKa
GuDViN [60]

Answer:

a  H2CO3 b HCO3- and c H+ and HCO3-

Explanation:

As the pKa value of phenol is more than that of carbonic acid(H2CO3), the carbonic acid will have high Ka value than that of phenol.

  The acid that contain high Ka value act as stong acid.From that point of view H2CO3 is a strong acid than phenol as the Ka value of carbonic acid is greater than that of phenol.

  The conjugate base of H2CO3 is bicarbonate ion(HCO3-)

c The species that predorminates at equilibrium are H+ and HCO3-

8 0
3 years ago
What is not matter in chemistry?? ​
Igoryamba

Answer:

중요하지 않은 것들의 예로는 생각, 감정, 빛, 에너지가 있습니다. ... 에너지 : 빛, 열, 운동 및 위치 에너지, 소리는 질량이 없기 때문에 물질이 아닙니다. 사물

Explanation:

Energy: Light, heat, kinetic and potential energy, and sound are non-matter because they are massless. Objects that have mass and are matter may emit energy.

5 0
3 years ago
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Which pair shares the same empirical formula?
ZanzabumX [31]

Answer:- 3. CH_3 and C_2H_6

Explanations:- An empirical formula is the simplest whole number ratio of atoms of each element present in the molecule/compound.

For example, the molecular formula of benzene is C_6H_6 . The ratio of C to H in it is 6:6 that could be simplified to 1:1. So, an empirical formula of benzene is CH.

In the first pair, the ratio of C to H in first molecule is 2:4 that could be simplified to 1:2 and  the empirical formula is CH_2 . In second molecule the ratio of C to H is 6:6 and it could be simplified to 1:1. and the empirical formula is CH. Empirical formulas are different for both the molecules of first pair and so it is not the right choice.

In second pair, C to H ratio in first molecule is 1:2, so the empirical formula is CH_2 . The C to H ratio for second molecule is 1:4, so the empirical formula is CH_4 . Here also, the empirical formulas are not same and hence it is also not the right choice.

In third pair, C to H ratio in first molecule is 1:3, so the empirical formula is CH_3 . In second molecule the C to H ratio is 2:6 and it is simplified to 1:3. So, the empirical formula for this one is also CH_3 . Hence. this is the correct choice.

In fourth pair, first molecule empirical formula is CH. Second molecule has 2:4 that is 1:2 mole ratio of C to H and so its empirical formula is CH_2 . As the empirical formulas are different, it is not the right choice.

So, the only and only correct pair is the third one. 3. CH_3 and C_2H_6

4 0
3 years ago
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