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2 years ago

Consider bowen's reaction series. which mineral would you expect to see as a phenocryst in a porphyritic basalt?

Chemistry

1 answer:

Maru [420]2 years ago

8 0

We will get Plagioclase as phenocryst in a porphyritic basalt using Bowmen's reaction series.

Porphyritic basalt is mafic i.e. it has low silica content and have higher melting point than felsic which have higher silica content . Porphyritic basalt's mineral composition is Calcium Plagioclase . Phenocryst is large crystal , early forming igneous rock.

Thus , on cooling plagioclase will be seen as phenocryst which is clear from Bowmen's reaction series because it is present on right side of series at higher temperature range in continuous branch in mafic region.

To know more about Bowmen's reaction series

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Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

$A=\log \frac{I_o}{I}$

$\log \frac{I_o}{I}=\epsilon \times C\times l$

where,

A = absorbance of solution

C = concentration of solution = $3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}$

l = path length = 2.5 mm = 0.25 cm

$I_o$ = incident light

$I$ = transmitted light

$\epsilon$ = molar absorptivity coefficient = $855dm^3mol^{-1}cm^{-1}$

Now put all the given values in the above formula, we get:

$\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)$

$\log \frac{I_o}{I}=0.6947$

$\frac{I_o}{I}=10^{0.6947}=4.951$

If we consider $I_o$ = 100

then, $I=\frac{100}{4.951}=20.198$

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light $I_A$ = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

$\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100$

$\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%$

Therefore, the percentage reduction in intensity is 79.80 %

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