Answer:
x= 226/3 or 75.33333333333333333333333333333
Step-by-step explanation:
14y+82=6x-20
y=25
Sub y=25 into 14y+82=6x-20
14y+82=6x-20
14(25)+82=6x-20
Calculate as follows:
14(25)+82=6x-20
350+82=6x-20
432=6x-20
Add twenty to both sides:
432+20=6x-20+20
452=6x-0
452=6x
Divide both sides by 6
452=6x
452/6=6x/6
452/6=x
x= 226/3 or 75.33333333333333333333333333333
Answer:
Solved using the <u>Exterior angle theorem</u>.
2x-5+x-17 = 128
3x-22 = 128
3x = 150
x = 50
Answer:
i don't know the answer BUT you can go to khan academy or tutor.com. Both can help :) good luck btw
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
Step-by-step explanation:
For quadratic equation ax^2 + bx + c = 0 to have two distinct real roots,
b^2 - 4ac must be positive.
b^2 - 4ac > 0
(k - 3)^2 - 4(3 - 2k) > 0
k^2 - 6k + 9 - 12 + 8k > 0
k^2 + 2k - 3 > 0
