All categories

3 years ago

Which of the lines below is a line of symmetry?

Mathematics

2 answers:

zhannawk [14.2K]3 years ago

8 0

Answer:

Step-by-step explanation:

elixir [45]3 years ago

4 0

Answer:

Both.

Step-by-step explanation:

You might be interested in

Help if your good at maths

tekilochka [14]

Let's make another angle y

Where y= 51° (corresponding angles )

and x+y= 180°. ( linear pair )

x+51°= 180° (y=51°)

x=180°-51°

x= 129°

<u>So the value of x is 129</u>°

Hope you got your answer !

4 0

3 years ago

Read 2 more answers

Help!!!!

Feliz [49]

Answer:

Step-by-step explanation:

<h3>Exponential Form :</h3><h3>(a^m*a^n ) = (a^m+n )</h3>

<h3>(only 7^-4 the term that can add to 7^-2 gives </h3><h3>= 7^-6 )</h3>

6 0

2 years ago

The mean clotting time of blood is 7.45 seconds with a standard deviation of 3.6 seconds. what is the probability that an indiv

Usimov [2.4K]

Less than 3 is about 10.75% and greater than 13 is about 6.18%.

To find these percents, you need to find the z-score for each value. Then, use your table to find the correct percent. Be sure to find the side above 13 when you use your chart.

For less than 3:
(3 - 7.45) / 3.6 = -1.24 = The percent below this is 0.1075

For greater than 13:
(13 - 7.45) / 3.6 = 1.54 = The percent above this is 0.0618

7 0

3 years ago

If r= 37 find the values of p, q, s

kkurt [141]

Answer:

ckfgfuf go he z v g b I g to

Step-by-step explanation:

c I'm x go bc to ggzh it ti

4 0

2 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago