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Dmitriy789 [7]
3 years ago
7

Which of the lines below is a line of symmetry?

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
8 0

Answer:

d

Step-by-step explanation:

elixir [45]3 years ago
4 0

Answer:

Both.

Step-by-step explanation:

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Someone help me fast please
lions [1.4K]

Answer:

86

Step-by-step explanation:

<u>Perimeter of WXY = WSY+WRX+XY</u>

<em>--> WSY = SY x 2</em>

--> WSY = 16 x 2 = 32

<em>Since it is an isosceles triangle, WRX = WSY</em>

--> WRX = 32

<em>--> Draw a straight line from W to XY to divide it into two halves assuming it to be point A. This would form a right angle triangle of WAX.</em>

<em>--> Solve it using the cos theta rule</em>

--> Angle = Angle X = 70°

    Hypotenuse = WRX = 32

    Adjacent = WA = ?

<em>--> Cos (Angle) = Adjacent/Hypotenuse</em>

    Cos (70) = WA/32

    WA = 10.9 rounded off to 11

--> WA=AY= 11

--> XY = WA + AY = 11+11 = 22

<em>--> Perimeter = WSY+WRX+XY</em>

    Perimeter = 32+32+22

    Perimeter = 86

Therefore, the perimeter of WXY is 86.

4 0
3 years ago
Ad is tangent to circle o at d. find ab. round to the nearest tenth if necessary
Naddik [55]
Check the picture below.

\bf 0=AB^2+6AB-121\implies \stackrel{\textit{using the quadratic formula}}{AB=\cfrac{-6 \pm \sqrt{6^2-4(1)(-121)}}{2(1)}}&#10;\\\\\\&#10;AB=\cfrac{-6 \pm \sqrt{520}}{2}\implies AB=\cfrac{-6 \pm \sqrt{4\cdot 130}}{2}&#10;\\\\\\&#10;AB=\cfrac{-6 \pm \sqrt{2^2\cdot 130}}{2}\implies AB=\cfrac{-6 \pm 2\sqrt{130}}{2}&#10;\\\\\\&#10;AB=-3\pm\sqrt{130}\implies AB=&#10;\begin{cases}&#10;\boxed{-3+\sqrt{130}}\\\\&#10;-3-\sqrt{130}&#10;\end{cases}

since the distance AB cannot be a negative value, thus is not -3-√(130).

3 0
3 years ago
Read 2 more answers
The line segment is rotated by 270 degrees counterclockwise about the origin to form C'D'. Which statement describes C'D'? C'D'
Elan Coil [88]

Answer:

  • A. C'D' is 4 units long

Step-by-step explanation:

According to the graph, CD is 5 - 1 = 4 units long.

Rotation doesn't change the length of the segment, so C'D' = CD = 4 units.

Correct choice is A.

7 0
2 years ago
Calculate the area of a regular octagon if the radius is 10 cm long.
charle [14.2K]

Answer:

Area is A≈282.8 cm  

Step-by-step explanation:

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3 years ago
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ser-zykov [4K]
\left\{\begin{array}{ccc}7x-2=2y\\3x=2y-1\end{array}\right\\\\substitution:\\\\3x=7x-2-1\\3x-7x=-3\\-4x=-3\ \ \ /:(-4)\\x=\frac{3}{4}\\\\2y=7\cdot\frac{3}{4}-2=\frac{21}{4}-2=\frac{21}{4}-\frac{8}{4}=\frac{13}{4}\\2y=\frac{13}{4}\ \ \ \ /:2\\y=\frac{13}{8}\\\\Answer:x=\frac{3}{4};\ y=\frac{13}{8}.
6 0
3 years ago
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