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3 years ago

Find the value of ab÷bc when a=6 b=0.9 and c=5

Mathematics

1 answer:

Fed [463]3 years ago

8 0

Answer:

1.2

The first step would to be to plug in your numbers for your variables, so

ab/bc= (6)(0.9)/(0.9)(5)

(6)(0.9)/(0.9)(5)

6*0.9=5.4

0.9*5=4.5

5.4/4.5=1.2

Step-by-step explanation:

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What is the simplified value of the exponential expression 27 Superscript one-third?

leva [86]

Answer:

simplified value of the exponential expression 27 Superscript one-third

27= 3×3×3

= $3^{3}$

answer is 3

Step-by-step explanation:

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2 years ago

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx....%7D%20%7D%20%7D%20%7D%20%20%3D%20%

andrey2020 [161]

First observe that if $a+b>0$ ,

$(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}$

Let $a=0$ and $b=x$ . It follows that

$a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}$

Now let $b=1$ , so $a^2+a=4x$ . Solving for $a$ ,

$a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2$

which means

$a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}$

Now solve for $x$ .

$x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2$

(note that we assume $2x-1\ge0$ )

$4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}$

(we omit $x=0$ since $2\cdot0-1=-1\ge0$ is not true)

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1 year ago

Which graph shows the solution to the equation 4x-4=4?

Mama L [17]

Answer:

Step-by-step explanation:

y = 4x - 4 is a line with y-intercept -4 and slope 1. Both graphs A and C show that line in blue.

y = 4 is a horizontal line through y = 4. Graph A shows that line.

Answer: A

5 0

3 years ago

1. Jane saved up 20 coins, all nickels and

kompoz [17]

Answer:

10 nickels and 10 quarters

Step-by-step explanation:

Given

Number of coins: 20

Vaiue of coins = $3.00

Required

Number of Nickels and Quarters;

<em>Let N =Nickels and Q =Quarters</em>

The total coins is represented as:

$N + Q = 20$

1 nickel is equivalent to $0.05 and 1 quarter is equivalent to $0.25; So

$0.05N + 0.25Q = 3$

Make N the subject of formula in the first equation

$N = 20 - Q$

Substitute this in the second equation

$0.05(20 - Q) + 0.25Q = 3$

$1 - 0.05Q + 0.25Q = 3$

Collect like terms

$-0.05Q + 0.25Q = 3 - 1$

$0.2Q = 2$

Multiply both sides by 5

$5 * 0.2Q = 2 * 5$

$Q = 10$

Recall that N = 20 - Q

$N = 20 - 10$

$N = 10$

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3 years ago

if an external point of a circle is at a distance equal to the diameter of the circle from the center of the circle, the length

jeka57 [31]

Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem

t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).

So t = √(3r^2) = √3r answer.

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3 years ago