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3 years ago

What is the value of x? Round to the nearest tenth Need help fast!!

Mathematics

1 answer:

lesantik [10]3 years ago

3 0

The answer is actually 7.0 because the lengths of the triangle are both going to be 5 and the hypotenuse is then 5 square root of 2 which is 7.07 so if you round it’s 7.0

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What is the value of 3x+3y?

NNADVOKAT [17]

Answer:

3(x+y)

Step-by-step explanation

this is the right answer

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3 years ago

A can of peas weighs 10 oz. Explain how you would make a graph to model the total weight of peas in terms of the number of cans

Vika [28.1K]

Ur x axis will be the number of cans and ur y axis will be the weight in oz

u will label ur x axis( the number of cans) in intervals of 1......from 0 to 4
u will label ur y axis (the weight) in intervals of 10....from 0 to 40

ur equation would be : y = 10x
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3 years ago

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Randy can run six-tenths of a mile every 4 minutes, but it takes Julie 5 minutes. By the time Julie has run for 20 minutes, how

katen-ka-za [31]

Answer:

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Step-by-step explanation:

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2 years ago

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

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tamaranim1 [39]

Answer:

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