9a) False, The dimensions are 10 x 20
b) True, 10 x 20 = 200
c) 10-6=4 (right side minus left side)
26-20=6 (bottom line minus top line)
d) True, Area of a triangle = (base x height) / 2
The base is 6 and the height is 4, so 6 x 4= 24 / 2 =12
e) True, the total area is equal to the triangle area plus the rectangles area.
so, 200+12= 212
17 = -13 - 8x .....add 13 to both sides
13 + 17 = -8x
30 = -8x...now divide both sides by -8
-30/8 = x...reduce
- 15/4 or -3 3/4 = x <===
Answer:
17.7 cm^2
Step-by-step explanation:
Use trig to find the height of the triangle. Then the area is bh/2.
Extend side BC to the right until it is vertically below point A. Draw a segment from point A vertically down until it intersects the extension of side BC. Call the point of intersection D. <D is a right angle.
Use triangle ABD to find the height, AD, of triangle ABC.
For <B of 37 deg, AD is the opposite leg. AB is the hypotenuse. The trig ratio that relates the opposite lefg to the hypotenuse is the sine.
sin B = opp/hyp
sin 37 deg = AD/13.1
AD = 13.1 * sin 37 deg
AD = 7.9
AD is the height of triangle ABC. BC is the base. We can find the area of triangle ABC.
area = bh/2
area = (4.5 cm)(7.9 cm)/2
area = 17.7 cm^2
6,635 should be standard form
Answer:
x = 
= 10.8
Step-by-step explanation:
Both problems are done the same way. I will do the first one and you do the second one. OK?
Move the radius x to make a right triangle. The 6 unit segment bisects the chord. So, the legs of the right triangle are 6 and 9
The use the Pythagorean theorem to find x, which is the hypotenuse of the right triangle. Now,
= 10.8
None of the answer choices are to the nearest tenth. So, I am confused about that.
In the second problem, the answer should be 11.2
