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3 years ago

If a line has a slope of four and contains the point -2, five what is its equation in point slope form

Mathematics

1 answer:

Otrada [13]3 years ago

3 0

Answer:

y - 5 = 4 (x - -2) or y - 5 = 4 (x + 2)

Step-by-step explanation:

Point-slope form:

y- y1 = m (x - x1 )

m = 4

x1 = -2

y1 = 5

fill in the blanks:

y - 5 = 4 (x + 2 )

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A rocket is launched from a height of 3m with an initial velocity of 15 m/s at what time will the rocket be 13m from the ground?

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1 year ago

Given that triangle ABC is a right triangle, select a set of possible side length measurements

Elza [17]

Answer:

4,5,6 / 6,8,10 / 5,12,13 / ....

Step-by-step explanation:

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1 year ago

What is 1 plus 2/3 over 1 minus 1/6

Setler79 [48]

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3 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

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3 years ago

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Alekssandra [29.7K]

Step-by-step explanation:

= 3 - 5

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