Answer:
L = 10.64°
Step-by-step explanation:
From the given information:
In triangle JKL;
line k = 9.6 cm
line l = 2.7 cm; &
angle J = 43°
we are to find angle L = ???
We can use the sine rule to determine angle L:
i.e
Using Pythagoras rule to find j
i,e
j² = k² + l²
j² = 9.6²+ 2.7²
j² = 92.16 + 7.29
j² = 99.45
j = 9.97
∴
Answer:
Step-by-step explanation:
Yes i guess
X^2 + y^2 = (3x^2 + 2y^2 - x)^2
2x + 2y f'(x) = 2(3x^2 + 2y^2 - x)(6x + 4y f'(x) - 1) = 36x^3 + 24x^2yf'(x) + 24xy^2 + 16y^3f'(x) - 4y^2 - 18x^2 - 8xyf'(x) + x
f'(x)(2y - 24x^2y - 16y^3 + 8xy) = 36x^3 + 24xy^2 - 4y^2 - 18x^2 - x
f'(x) = (36x^3 + 24xy^2 - 4y^2 - 18x^2 - x)/(2y - 24x^2y - 16y^3 + 8xy)
f'(0, 0.5) = -4(0.5)^2/(2(0.5) - 16(0.5)^3) = -1/(1 - 2) = -1/-1 = 1
Let the required equation be y = mx + c; where y = 0.5, m = 1, x = 0
0.5 = 1(0) + c = 0 + c
c = 0.5
Therefore, the tangent line at point (0, 0.5) is
y = x + 0.5
