Answer:
4.72 hours/day
Step-by-step explanation:
Mean time spent watching TV (μ) = 2.8 hours a day
Standard deviation (σ) = 1.5 hours a day
The 90th percentile (upper 10%) of a normal distribution has an equivalent z-score of roughly z = 1.282. The minimum time spent watching TV, X, at the 90th percentile is:
On a typical day, you must watch at least 4.72 hours of TV to be in the upper 10%.
Answer:
we need circumference which is pie times d
9 pie
Step-by-step explanation:
-2(2b-3)
Multiply the bracket by -2
Whenever multiplying a -negative number with a -negative number= + positive number.
(-2)(2b)(-2)(-3)
-4b+6
Answer: -4b+6
Answer:
It's the PURPULE one
Step-by-step explanation:
BTW can u pls help me in my question thanks