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3 years ago

Find product of :(2x-y)(2x+3y).

Mathematics

1 answer:

Ierofanga [76]3 years ago

7 0

Answer: 4x² + 4xy - 3y²

Concept:

When encountering questions that ask for simplifying algebraic expressions, using the FOIL method would be easier:

First, which means multiplying the first terms together;
Outer, which means that we multiply the outermost terms when the binomials are placed side by side;
Inner, which means multiply the innermost terms together;
Last, which means that we multiply the last term in each binomial together.

Solve:

Given

(2x - y) (2x + 3y)

Expand parentheses and apply the FOIL method

=4x² + 6xy - 2xy - 3y²

Combine like terms

=4x² + (6xy - 2xy) - 3y²

= $\boxed{4x^2+4xy-3y^2}$

Hope this helps!! :)

Please let me know if you have any questions

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Luda [366]

Answer:

The sum of the first 100 terms is 60400

Step-by-step explanation:

* Lets revise the arithmetic sequence

- There is a constant difference between each two consecutive

numbers

- Ex:

# 2 , 5 , 8 , 11 , ……………………….

# 5 , 10 , 15 , 20 , …………………………

# 12 , 10 , 8 , 6 , ……………………………

* General term (nth term) of an Arithmetic sequence:

- U1 = a , U2 = a + d , U3 = a + 2d , U4 = a + 3d , U5 = a + 4d

- Un = a + (n – 1)d, where a is the first term , d is the difference

between each two consecutive terms n is the position of the

number

- The sum of first n terms of an Arithmetic sequence is calculate from

Sn = n/2[a + l], where a is the first term and l is the last term

* Now lets solve the problem

- We will use method (1)

- From the table the terms of the sequence are:

10 , 22 , 34 , 46 , 58 , 82 , 94 , ............., where 10 is the first term

∵ an = a1 + (n - 1) d ⇒ explicit formula

∵ a1 = 10 and a2 = 22

∵ d = a2 - a1

∴ d = 22 - 10 = 12

- The 100th term means the term of n = 100

∴ a100 = 10 + (100 - 1) 12

∴ a100 = 10 + 99 × 12 = 10 + 1188 = 1198

∴ The 100th term is 1198

- Lets find the sum of the first 100 terms of the sequence

∵ Sn = n/2[a1 + an]

∵ n = 100 , a = 10 , a100 = 1198

∴ S100 = 100/2[10 + 1198] = 50[1208] = 60400

* The sum of the first 100 terms is 60400

7 0

3 years ago

Find product of :(2x-y)(2x+3y).​

Find product of :(2x-y)(2x+3y).