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2 years ago

Find product of :(2x-y)(2x+3y).

Mathematics

1 answer:

Ierofanga [76]2 years ago

7 0

Answer: 4x² + 4xy - 3y²

Concept:

When encountering questions that ask for simplifying algebraic expressions, using the FOIL method would be easier:

First, which means multiplying the first terms together;
Outer, which means that we multiply the outermost terms when the binomials are placed side by side;
Inner, which means multiply the innermost terms together;
Last, which means that we multiply the last term in each binomial together.

Solve:

Given

(2x - y) (2x + 3y)

Expand parentheses and apply the FOIL method

=4x² + 6xy - 2xy - 3y²

Combine like terms

=4x² + (6xy - 2xy) - 3y²

= $\boxed{4x^2+4xy-3y^2}$

Hope this helps!! :)

Please let me know if you have any questions

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2 years ago

A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so

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and flows out at a rate

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$\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}$

Integrate both sides. By the fundamental theorem of calculus,

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}$

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)$

$\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}$

$\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}$

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After 1 hour = 60 minutes, the tank will contain

$A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131$

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3 years ago

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2 years ago

Find product of :(2x-y)(2x+3y).​

Find product of :(2x-y)(2x+3y).