The list of possible outcomes in the question is totally incomprehensible. But from our vast experience with questions like this and dice in general, we know there are 36 of them.
Now, here are all the ways to roll a total of 9:
3, 6
6, 3
4, 5
5, 4
Four of the 36 possible rolls result in a 9.
So the probability (with honest dice) is 4/36 = 1/9 = 11.1% .
If
and
, separate variables in the differential equation to get

Integrate both sides:

Use the initial condition to solve for
:

Then the particular solution to the initial value problem is

(A)
Keiko has a total of $5200
x is the amount of money in larger account
y is the amount of money in smaller account
x - y = $900
and x + y = $5200
<u>This creates two simultaneous equations:</u>
x - y = $900 ... (i)
x + y = $5200 ... (ii)
Adding (i) and (ii) :
2x = $6100 , x = $3050
y = x - $900 = $3050 - $900 = $2150
The amount of money in larger account (x) = $3050
The amount of money in smaller account (y) = $2150
The answer is o+ Hope this helped.