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3 years ago

SOMEONE PLEASE HELP ME SOOOOOON

Mathematics

1 answer:

irinina [24]3 years ago

6 0

Answer:

the dilation is a reduction

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What is the area of this figure

Leviafan [203]

First, you must observe the figure and realize that you have a parallelogram and a rectangle.
Therefore, the total area will be the sum of the area of the parallelogram plus the area of the rectangle.
Palelogram area:
A1 = b * h
We have then
b = root ((- 4 - (- 10)) ^ 2+ (2-2) ^ 2) = 6
h = root ((- 7 - (- 7)) ^ 2+ (3-2) ^ 2) = 1
A1 = (6) * (1) = 6 units ^ 2
Rectangle area
A2 = L * W
We have then:
L = root ((1 - (- 2)) ^ 2 + (- 3 - (- 4)) ^ 2) = 3.16227766
W = root ((- 4 - (- 2)) ^ 2+ (2 - (- 4)) ^ 2) = 6.32455532
A2 = (3.16227766) * (6.32455532)
A2 = 20 units ^ 2
The total area is the sum of both ares:
A = A1 + A2
A = 6 + 20
A = 26 units ^ 2
Answer:
the area of this figure
A = 26 units ^ 2

3 0

4 years ago

If Fred feeds 12 horses for two weeks with 25 bales of hay, how many bales of hay does he need to feed 15 horses for two weeks?

Dvinal [7]

Answer:

He needs 31.25 bales of hay to feed 15 horses for two weeks

Step-by-step explanation:

This question can be solved using a rule of three.

25 bales of hay feed 12 horses. How many feed 15 horses?

12 horses - 25 bales of hay

15 horses - x bales of hay

$12x = 25*15$

$x = \frac{25*15}{12}$

$x = 31.25$

He needs 31.25 bales of hay to feed 15 horses for two weeks

7 0

3 years ago

PLEASE HELP BRAINLIEST

Sliva [168]

Answer:

I cant see whats the question

Step-by-step explanation:

8 0

3 years ago

The formula P=4s gives the perimeter P of a square with side length s. What is the perimeter sign with a side length of 15 inche

olchik [2.2K]

Answer:

p=60

Step-by-step explanation:

p=4(15)

p=60

3 0

3 years ago

A mass oscillating up and down on the bottom of a spring can be modeled as harmonic motion. if they weight is displaced a maximu

snow_tiger [21]

9514 1404 393

Answer:

1.63 cm (across the centerline from release)

Step-by-step explanation:

If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...

h(t) = -7cos(2πt/4)

h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm

That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.

If it is released from <em>above</em> the resting position, it will be 1.63 cm <em>below</em> the resting position at t=1.15 seconds.

6 0

3 years ago