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2 years ago

Simplify the expression: X^2 (2x + 3)

Mathematics

2 answers:

jeka942 years ago

7 0

Answer:

Step-by-step explanation:

Natasha2012 [34]2 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

-1 3/5 divided by -2/3

Cloud [144]

<h2>Answer:</h2>

12/5

alternative forms:

2 2/5, or 2.4

<h2>Step-by-step explanation:</h2>

-1 3/5÷ -2/3

convert mixed number to an improper fraction

-8/5÷ -2/3

divide

8/5•3/2

reduce numbers

4/5•3

multiply

---------

12/5

---------

7 0

3 years ago

Read 2 more answers

A truck driver drove 48 miles in 45 minutes.At this rate,how many miles can the truck drive in one hour?

murzikaleks [220]

Answer:

64 miles

Step-by-step explanation:

Number of miles driven in 45 minutes = 48 miles

We need to find how many miles will the truck drive drive in one hour. Since the rate is the same, the distance covered in each minute remains the same.

Number of miles driven in 1 minute = miles

Since, 1 hour = 60 minutes, we can write:

The number of miles driven in 1 hour (60 minutes) = miles

This means the truck driver can drive 64 miles in an hour.

HOPE THIS HELPS! :)

7 0

3 years ago

Read 2 more answers

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.