Answer:
The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
Sample of 421 new car buyers, 75 preferred foreign cars. So 
85% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).
Answer: Your answer would be -120
Step-by-step explanation: Remove Parentheses (3 + 3) add them together and make it 6 and plug in the 6 into the equation. -4 x 6 x 5. Then, you multiply the numbers together and get -120. There is no inverse for -120 since both sides aren't equal.
I hope this helps you!!
The equation whose solution is the given quantity is 90,000,000 = 2,000,000w + 15,000w where w = $44.67
<h3>Equation</h3>
B = xz + yw
Where,
- B = Total cost = 90
- x = number of fighter plane = 20
- y = tons of wheat = 15,000
- w = cost of each tons of wheat
- z = cost of fighter plane
- z = 100,000w
B = xz + yw
90,000,000 = (20 × 100,000w) + (15,000 × w)
90,000,000 = 2,000,000w + 15,000w
90,000,000 = 2,015,000w
w = 90,000,000 / 2,015,000
= 44.6650124069478
Approximately,
w = $44.67
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