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Lesechka [4]
3 years ago
8

A car is traveling at 20.0 m/s, and the driver sees a traffic light. turn red. After 0.530 s (the reaction time), the driver app

lies the brakes,. and the car decelerates at 7.00 m/s2. What is the stopping distance of the. car, as measured from the point where the driver first sees the red light?
Mathematics
1 answer:
slava [35]3 years ago
5 0
Before the driver applies the brakes ( with the reaction time ):
d 1 = v0 · t = 20 m/s · 0.53 s = 10.6 m
After that: 
v = v0 - a · t1  
0 = 20 m/s - 7 · t1
7 · t1 = 20
t1 = 2.86 s
d 2 = v 0 · t1 - a · t1² / 2
d 2 = 20 m/s · 2.86 s - 7 m/s² · (2.86 s)²/2 = 57.2 m - 28.6 m = 28.6 m
d = d 1 + d 2 = 10.6 m + 28.6 m = 39.2 m
Answer: the stopping distance of a car is 39.2 m.
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Set up a system of linear equations to represent the scenario. Solve the system by using Gaussian elimination or Gauss-
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<h3><u>Distributions</u></h3>

Given that Sylvia invested a total of $27,000, and she invested part of the money in a certificate of deposit (CD) that earns 3% simple interest per year, she invested in a stock that returns the equivalent of 7% simple interest, and she invested in a bond fund that returns 2%, and she invested three times as much in the stock as she did in the CD, and earned a total of $1140 at the end of 1 yr, to determine how much principal did she put in each investment, the following calculation must be made:

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Learn more about distribution in brainly.com/question/10250387

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