<h3>Answer: C) none of the equations are identities</h3>
If you plugged theta = 0 into the first equation, then you would have
sin(45) + cos(45) = sin(0) + cos(0)
sqrt(2) = 1
which is a false equation. We don't have an identity here.
The same story happens with the second equation. Plug in theta = 0 and it becomes
cos(60) - sin(60) = cos^2(0) + tan(0)
1/2 - sqrt(3)/2 = 1 + 0
-0.37 = 1
which is false.
Answer:
Theanswer is 4/27.
Step-by-step explanation:
given that, F(x) = 4×(1/3)^x
now , F(3)= 4×(1/3)^3 ( putting value of x)
or, F(3) = 4×(1/27)
therefore, F(3)= 4/27... ans
<em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
y = 3/5 x+3
Step-by-step explanation:
two points on the graph
(-5,0) (0,3)
the y intercept is 3 (this is where it crosses the y axis)
the slope is
change in y 0 to 3 up 3
------------------ = -------------- = ------- = 3/5
change in x -5 to 0 right 5
we can tell the slope is positive because it goes from bottom left to top right
a negative slope goes from top left to bottom right
slope intercept form is
y=mx+b
y = 3/5 x+3