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Jobisdone [24]
2 years ago
14

Which equation of a line passing through the point (-2, 2) with a y-intercept of 1?

Mathematics
1 answer:
Sholpan [36]2 years ago
7 0

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have y-intercept b = 1. Therefore y = mx + 1.

The graph passing through the point (-2, 2). Substitute the coordinates to the equation:

2 = m(-2) + 1       <em>subtract 1 from both sides</em>

1 = -2m      <em>divide both sides by -2</em>

m = -1/2

<h3>Answer: B. y = -1/2 x + 1</h3>
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How many of the scores from the group that studied in question eight are in one mean absolute deviation of the mean? Which score
n200080 [17]

Answer:

93

Step-by-step explanation:

<u><em>Add all of the numbers and divide them by the number of numbers there are.


</em></u><em>Hope this helped  ·ω·</em>

4 0
2 years ago
Help? Please?<br> I really suck at geometry
Maslowich

Answer:

x = 14

y = 4

Explanation:

Ok so, just from looking at the two triangles i can tell they're congruent right triangles. I used different colors to show which sides of the triangle correspond and are equal to each other in my attatched photo.

So the side thats equal to x is the same length as the side that's equal to y+10 on the other triangle.

So we can write the equation x = y + 10.

Using this same method, the side that's equal to x + 2 is the same length as the side that's equal to 4y on the other triangle.

So, we can write the equation 4y = x + 2.

Now we have the equations \left \{ {{x=y+10} \atop {4y=x+2}} \right. you could rewrite to be in slope- intercept form so they're easier to graph. But a graphing calculator online would plot it just fine.

If you graph these two equations they'll intersect at the solution ( 14, 4 ). I'll include the graph in my images as well.

To check your answer, you can plug in x and y and see if the triangle sides end up being the same length. I did and it was correct.

8 0
3 years ago
HELP ASAP
Ilya [14]

Answer:

Step-by-step explanation:

it is an adjacent/linear pair

5 0
3 years ago
Find the GCF of the terms of the polynomial. 30x3 + 16x5<br> a. x3<br> b. 2x3<br> c. 2x5<br> d. 16x
Vladimir79 [104]
You can take out 2x^3 from both terms making it
2x^3 (15+8x^2)
Answer is B
3 0
3 years ago
This last one I need help on too
ExtremeBDS [4]

Answer:

x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}

Step-by-step explanation:

simplify \frac{-3}{x-2} by putting the negative sign on the outside. \frac{2x}{x-1}-\frac{2x-5}{x^2-3x+2}=-\frac{3}{x-2}

find the LCM of the denominators. It is (x-1)(x-2). Multiply by the LCM:

\frac{2x}{x-1}\left(x-1\right)\left(x-2\right)-\frac{2x-5}{x^2-3x+2}\left(x-1\right)\left(x-2\right)=-\frac{3}{x-2}\left(x-1\right)\left(x-2\right)

Simplify:

2x\left(x-2\right)-\left(2x-5\right)=-3\left(x-1\right)

solve: x=\frac{3}{4}+i\frac{\sqrt{7}}{4},\:x=\frac{3}{4}-i\frac{\sqrt{7}}{4}

3 0
3 years ago
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