Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:

this is equivalent to:

thus, we can conclude that
x= 3.
Answer:
I don't think you can..
Step-by-step explanation:
Answer:
a median
b center
Step-by-step explanation:
The middle value of a set of numbers is the median
The mean is the average value and the range is the largest minus the smallest.
This value is a measure of the center ( or a measure of the middle)
The range is a measure of the spread