Answer:
Let x = number of gate tickets, ($1.50)
:
Since there were 600 tickets sold, let (600-x) = the $1 tickets
:
1.50 tickets + $1 tickets = $700
:
1.5x + 1(600 - x) = 700
1.5x - x = 700 - 600
.5x = 100
x = 100/.5
x = 200 ea 1.50 tickets sold at the gate
;
;
Check: there were 600 - 200 = 400 ea $1 tickets sold
1.50(200) + 1(400) = $700
Answer:
The time interval when
is at 
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between 
The schematic free body graphical representation of the above illustration was attached in the file below and the point when
is at 4 is obtained in the parabolic curve.
So,
is at 
Taking the integral of the time interval in order to determine the distance; we have:
distance = 
= 
= By using the Scientific calculator notation;
distance = 106.109 m
F(x) = x (x^3 - x^2 + x + 1)
Answer:
all I know is how to get y but y=122
Step-by-step explanation:
y=3(40)+2
y=120+2
y=122
sorry but I dont know what to do for x