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Whitepunk [10]
3 years ago
5

What is the area of the figure in square millimeters and in square centimeters?

Mathematics
1 answer:
arlik [135]3 years ago
7 0
The answer to this equation is C, 2925 mm^2 and 29.25 cm^2.  
You might be interested in
What are the domain and range of f(x) = 2x - 41?
Darina [25.2K]

The domain of the function is a (-∞, 0) and the range of the function will be f(x) < 0. Then the correct option is C.

<h3>What are domain and range?</h3>

The domain means all the possible values of x and the range means all the possible values of y.

The function is given below.

f(x) = 2x – 41

Then the domain of the function is a (-∞, 0) and the range of the function will be f(x) < 0.

Then the correct option is C.

More about the domain and range link is given below.

brainly.com/question/12208715

#SPJ1

3 0
2 years ago
PLEASE HELP! SUPER EASY QUESTION! THANK YOU!
kobusy [5.1K]

Answer:

Step-by-step explanation:

a+pR^2-2pr^2, since R=15 and r=7.5

A=225p-112.5p

A=112.5p

a= 353.25ft^2

8 0
3 years ago
Read 2 more answers
What is the volume of the cone with a radius of 10ft and a height of 21ft?round to the nearest cubic foot
Ivan
Volume of cone is 2200ft
3 0
3 years ago
(05.03 LC)
never [62]

Answer:

The correct answer is x = -5

Step-by-step explanation:

All vertical lines can we written in terms of x = (a number). You can find this number in the ordered pair under the x-coordinate. In this case it is -5.

8 0
3 years ago
Jade buys a blouse and a skirt for 3/6 of their original price. Jade pays a total of $31 for the two items. If the original pric
Damm [24]

Answer:

3/4 times 18= 13.5

31.5-13.5=18  

It cost 18 dollars for the skirt with a discount.

It cost 13.5 for the blouse as opposed to the original price of 18 dollars.

18(skirt)+13.5(blouse)=31.5

If you set up a proportion to find the original price of the skirt you will get the answer.  

18/x=75/100

75x=18 times 100

75x=1800

75x/75=1800/75

x=24  

The original price of the skirt is 24 dollars.

Step-by-step explanation:

4 0
3 years ago
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