Answer: 0, π, 2π
Nevertheless, that is not an option. I see two possibilities: 1) the options are misswirtten, 2) the domain is not well defined.
If the domain were 0 ≤ θ < 2π, then 2π were excluded of the domain ant the answer would be 0, π.
Explanation:
1) The first solution, θ = 0 is trivial:
sin (0) - tan (0) = 0
0 - 0 = 0
2) For other solutions, work the expression:
sin(θ) + tan (-θ) = 0 ← given
sin (θ) - tan(θ) = 0 ← tan (-θ) = tan(θ)
sin(θ) - sin (θ) / cos(θ) = 0 ← tan(θ) = sin(θ) / cos(θ)
sin (θ) [1 - 1/cos(θ)] = 0 ← common factor sin(θ)
⇒ Any of the two factors can be 0
⇒ sin (θ) = 0 or (1 - 1 / cos(θ) = 0,
sin(θ) = 0 ⇒ θ = 0, π, 2π
1 - 1/cos(θ) = 0 ⇒ 1/cos(θ) = 1 ⇒ cos(θ) = 1 ⇒ θ = 0, 2π
⇒ Solutions are 0, π, and 2π
In fact if you test with any of those values the equation is checked. The only way to exclude one of those solutions is changing the domain.
Conquered the Macedonian Satrapies and won the Seleucid-Mauryan war.
The correct answer is y=-3x-10
when a line is parallel to another line that means the slip of the lines are going to be the same and since the y-intercept of the other line was given to you, you would just put them together in one equation.
Hello there,
Well to find the total time you would have to set up a proportion...
6 / 3/5 = x / 1
Now you crosss multiply and divide...
6 * 1 = 6
6 / 3/5 =30/3 = 10
Answer: 10 hours
Hope I helped!!
-Char
Option D:
ΔCAN ≅ ΔWNA by SAS congruence rule.
Solution:
Given data:
m∠CNA = m∠WAN and CN = WA
To prove that ΔCAN ≅ ΔWNA:
In ΔCAN and ΔWNA,
CN = WA (given side)
∠CNA = ∠WAN (given angle)
NA = NA (reflexive side)
Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.
Hence option D is the correct answer.
