Answer:
4x^2 + 8x + 4
4(x^2 + 2x + 1) - remove GCF of 4
4(x + 1)(x + 1) - factor
4(x + 1)^2 - collect like terms
Step-by-step explanation:
Then also expand it out by distributing:
21x^3 + 35x²
Form 1:
21x^3 + 35x² - unfactored
Form 2:
7x²(3x + 5) - factored with GCF of 7x² brought to the front
Update:
You could also multiply two binomials and make a quadratic.
Example:
(7x + 2)(3x + 5)
7x(3x + 5) + 2(3x + 5)
= 21x² + 35x + 6x + 10
= 21x² + 41x + 10
A.
To solve, you need to get the variable by itself.
Order of operations:
Square root both sides.
(x-5)= plus/minus root 3, as 3 is not a perfect square.
Now you need to add 5 to both sides to get it to disappear on the side with the x.
x=root3 +or - 5, which can be rearranged so that 5 is the first term.
Answer: 55
Step-by-step explanation:
just add 41.5 on 13.5 and that is x
Answer:
an expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable(s).
