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3 years ago

in 2008 election there was 28 blue states and22 red states express the red states and blue states as fractions lowest terms

Mathematics

1 answer:

seropon [69]3 years ago

4 0

Blue states.) 14/25
Red states.)11/25

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Staples sells pencils in packs of 12 pencils for 3.50. Office max sells pencils in packs of 15pencils for 6.50.what is the diffe

love history [14]

We are given

Staples sells pencils in packs of 12 pencils for 3.50

so, staples cost is

$=\frac{3.50}{12}$ per pencil

$=0.29167$ per pencil

Office max sells pencils in packs of 15 pencils for 6.50

so, office max cost is

$=\frac{6.50}{15}$ per pencil

$=0.4333$ per pencil

now, we can find their differences

$=0.4333-0.29167$ per pencil

$=0.14$ per pencil............Answer

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2 years ago

0 Domain: Range: Function? what is the domain

Anna35 [415]

Answer:

Domain are any value of x that's make y to be defined

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3 years ago

Read 2 more answers

64=[(96 divided by 8) times 5]-42

bogdanovich [222]

Answer:

that statement is not true

Step-by-step explanation:

64=[(96÷8)5}-42

64={(12)5} - 42

64= (60)-42

64=18

but that with subtraction. if you multiply 60 by negative 42 you get -2520 which is still not true

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3 years ago

M Find the measure of the angles.

nignag [31]

A central angle θ in a circle of radius 5 m is subtended by an arc of length 6 m. Find the measure of θ in degrees. (Round your answer to one decimal place.)

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2 years ago

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(X^2+y^2+x)dx+xydy=0 Solve for general solution

aksik [14]

Check if the equation is exact, which happens for ODEs of the form

$M(x,y)\,\mathrm dx+N(x,y)\,\mathrm dy=0$

if $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ .

We have

$M(x,y)=x^2+y^2+x\implies\dfrac{\partial M}{\partial y}=2y$

$N(x,y)=xy\implies\dfrac{\partial N}{\partial x}=y$

so the ODE is not quite exact, but we can find an integrating factor $\mu(x,y)$ so that

$\mu(x,y)M(x,y)\,\mathrm dx+\mu(x,y)N(x,y)\,\mathrm dy=0$

is exact, which would require

$\dfrac{\partial(\mu M)}{\partial y}=\dfrac{\partial(\mu N)}{\partial x}\implies \dfrac{\partial\mu}{\partial y}M+\mu\dfrac{\partial M}{\partial y}=\dfrac{\partial\mu}{\partial x}N+\mu\dfrac{\partial N}{\partial x}$

$\implies\mu\left(\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}\right)=M\dfrac{\partial\mu}{\partial y}-N\dfrac{\partial\mu}{\partial x}$

Notice that

$\dfrac{\partial N}{\partial x}-\dfrac{\partial M}{\partial y}=y-2y=-y$

is independent of x, and dividing this by $N(x,y)=xy$ gives an expression independent of y. If we assume $\mu=\mu(x)$ is a function of x alone, then $\frac{\partial\mu}{\partial y}=0$ , and the partial differential equation above gives