Answer:
<h2>Gold</h2>
Explanation:
Assume Gold trait =P ,
Purple= p,
Given:
Gold (P) is dominant over purple(p), so P is dominant over p.
If the bear is homozygous pp ( recessive) then bear will look purple,
If the bear is heterozygous Pp, then bear will look gold,
If the bear is homozygous DD( dominant), then the bear will look GOLD,
<h2>Evolution of phylogenies </h2>
Explanation:
- The genome of the endosymbiont is all the more firmly identified with individuals from the gathering in which it initially developed, while the nuclear genome of the inundating living being has its own evolutionary trajectory.
- The accumulation of various inheritable attributes after some time which prompted the arrangement of another species
- Nuclear and organellar genes advanced at various rates, clouding developmental connections.
- Some mitochondrial genomes have been decreased definitely in size, losing a large number of the protein genes encoded in creature mtDNA just as a few or all mtDNA-encoded tRNA genes.
- At ∼6 kb in size, the mitochondrial genome of Plasmodium falciparum (human intestinal sickness parasite) and related apicomplexans is the littlest known, harboring just three protein genes, profoundly divided and improved little subunit (SSU) and enormous subunit (LSU) rRNA genes, and no tRNA genes.
- In stamped differentiate, inside land plants, mtDNA has extended generously in size (>200 kb) if not in coding limit, with the biggest known mitochondrial genome right now.
Ozone would be the secondary pollutant because it is caused when two primary pollutants react. Hope this helps!
<span> D. In a forward-biased setup, large numbers of charge carriers will be pulled across the </span>junction<span> and result in a large current.</span>
