P = 6s
42a +18 = 6s
s = 7a + 3
s is the side of hexagon
p is the perimeter of the hexagon
Answer: y= - 19/6+x/6
Step-by-step explanation: maybe
Answer:
≈ 1800 mm³
Step-by-step explanation:
Volume of the figure above will be given by the formula
Cross section area × length
In this case;
Cross section area will be;
Area of the square + area of the two semi circles
12× 12 + 2(3.14 × 6 ×6/2)
= 144 + 3.14 ×36
= 257.04 mm²
Volume = Cross section area × Length
= 257.04 × 7
= 1799.28 mm³
<u> ≈ 1800 mm³</u>
Answer:
m<N = 32°
m(NQ) = 106°
Step-by-step explanation:
Inscribed angle = ½ of the measure of the intercepted arc (inscribed angle theorem)
<N is an inscribed angle
It's intercepted arc = arc MP = 64°
Therefore,
m<N = ½(64°)
m<N = 32°
m<P = ½(m(NQ)) (inscribed angle theorem)
53° = ½(m(NQ))
Multiply both sides by 2
2*53° = m(NQ)
106° = m(NQ)
m(NQ) = 106°
From the diagram, we know that it is an angle that adds up to 360
So
x+4x+2x+10+5x+50=360
Gather like terms
12x+60=360
Move sixty to the other side as a negative number
12x=300
Divide both sirs by twelve
x is equal to 25
AOB is 2x+10
Sub x in 2*25+10
AOB is 60
BOC is 5x+50
5*25+50, which is 175
BOD is x+2x+10
Which is 3x+10
Sub x
3*25+10 which is 85
:)
